In circle G with m<FJH=31° , Find the angle measure of minor arc FH​

62°

Step-by-step explanation:

Inscribed Angle Theorem

Inscribed angles measures are 1/2 of the arc they create.

m∠FJH x 2 = arc FH

Just take the 31° and double it.

goog may have it for you

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl