Area: Change in Dimensions A rectangle FGHJ has a width of 3 inches and a length of 7 inches
a) What is the Area of the rectangle?
b) What is the Area of the new rectangle if you double the width of FDHJ? How did you find it? How much bigger or smaller did the new Area get?
c) What is the Area of the new rectangle if you double the width and length of rectangle FDHJ? How did you find it? How much bigger or smaller did the new Area get
compared to the area of FDHJ?
d) Now choose a different shape of your liking and give it your own dimensions. Answer questions a), b), c) and d) for the shape you chose.
e) Can you generalize what happens if you change one of the dimensions of a shape and what happens when you change both dimensions of the shape?

answer: no

step-by-step explanation:

you are only given the cost not the amount of pounds.

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt

your answer is b.

x = 33.9

y = 65.6

step-by-step explanation: