Consider the initial value problem y' + 6y = {0 if 0 < or equal to t < or equal to 2
12 if 2 < or equal to t < or equal to 6
0 if 6 < or equal to t < or equal to infinity}
a. Take the Laplace transform of both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transform of y(t) by Y(s). Do not move any terms from one side of the equation to the other (until you get to part (b) below).
b. Solve your equation for Y(s).
c. Take the inverse Laplace transform of both sides of the previous equation to solve for y(t).

y' + 6y = f(t)

where

You can write f(t) in terms of the unit step (i.e. Heaviside theta) function u(t), which is defined as

Then the DE is written as

y' + 6y = 12 u (t - 2) - 12 u (t - 6)

(a) Take the Laplace transform of both sides:

LT[y' + 6y] = LT[12 u (t - 2) - 12 u (t - 6)]

s Y - y (0) + 6Y = 12 (exp(-2s) - exp(-6s))/s

(b) Solve for Y :

(s + 6) Y = 12 (exp(-2s) - exp(-6s))/s + y (0)

Y = 12 (exp(-2s) - exp(-6s))/(s (s + 6)) + y (0)/(s + 6)

(c) Take the inverse transform:

LT⁻¹ [Y] = LT⁻¹[12 (exp(-2s) - exp(-6s))/(s (s + 6)) + y (0)/(s + 6)]

y = 12 LT⁻¹ [(exp(-2s) - exp(-6s))/(s (s + 6))] + y (0) LT⁻¹ [1/(s + 6)]

y = 12 u (t - 2) LT⁻¹ [1/(s (s + 6))] - 12 u (t - 6) LT⁻¹ [1/(s (s + 6))] + y (0) exp(-6t )

For the remaining inverse transform, break up into partial fractions:

1/(s (s + 6)) = a/s + b/(s + 6)

1 = a (s + 6) + bs

1 = (a + b) s + 6a

==>   6a = 1, a + b = 0   ==>   a = 1/6, b = -1/6

y = 2 u (t - 2) LT⁻¹ [1/s - 1/(s + 6)] - 2 u (t - 6) LT⁻¹ [1/s - 1/(s + 6)] + y (0) exp(-6t )

y = 2 u (t - 2) (1 - exp(-6t )) - 2 u (t - 6) (1 - exp(-6t )) + y (0) exp(-6t )

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.