Can you answer this math homework? Please!

(3.5,-2)

Step-by-step explanation:

To solve this problem, all we have to do is plug in y=-2 into either equations from step one to find the coordinate. To make sure we have the right x-coordinate, let's plug in y for both equations.

4x-7y=28        [plug in y=-2]

4x-7(-2)=28    [multiply]

4x+14=28       [subtract both sides by 14]

4x=14              [divide both sides by 4]

x=3.5

6x-5y=31        [plug in y=-2]

6x-5(-2)=31    [multiply]

6x+10=31       [subtract both sides by 10]

6x=21             [divide both sides by 6]

x=3.5

Now, we know the solution to the system is (3.5,-2).

(3.5, -2)

Step-by-step explanation:

Hi there!

We are given a system of equations, and the value for y is already solved (y=-2)

We want to find the value of x

To do that, substitute -2 as y into either one of the equations in the system (the system has the equations 4x-7y=28 and 6x-5y=31) and solve for x

Let's use 4x-7y=28, although picking 6x-5y=31 is completely fine

Substitute -2 as y into the equation

4x-7(-2)=28

Multiply

4x+14=28

Subtract 14 from both sides

4x=14

Divide both sides by 4 and simplify

x=7/2, or 3.5

We found the value of x in the system

Substitute the values of x and y into a point form (x, y)

The solution is (3.5, -2)

Hope this helps!

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.