How many distinct permutations can be formed using the letters of the word robberies

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this is the answer;No. of Permutations=3360.

Step-by-step explanation:

Suppose that, out of

n

things,

r

1

are of first type,

r

2

are of

second type,

r

3

are of third type,..., where

r

1

+

r

2

+

r

3

+

...

=

n

.

Then, no. of possible distinct permutations is given by

n

!

(

r

1

!

)

(

r

2

!

)

(

r

3

!

)

...

In our Example, there are total

8

letters in the word INFINITY ,

out of which,

3

letters are of one type (i.e., the letter I ),

2

are of second type (i.e., the letter N ) and the remaining

3

are

a precentage of 6th graders. the population is all 6th graders. let me know if i'm wrong, i hope this ! : )

step-by-step explanation:

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w