You hit a tennis ball with an initial vertical velocity of of 10 ms The ball leaves the tennis racket 2 meters above the ground How much time does your opponent have before the ball hits the ground on the other side of the net

1.02secs

Step-by-step explanation:

Using the equation of motion

v = u+at

Since the ball moves upward then:

a = -g

Substitute into the formula

v = u-gt

Given the following

Initial velocity u = 10m/s

Final velocity v = 0m/s (on the ground)

g = 9.8m/s²

Required

Time t

Substitute the given values into the formula

0 = 10-9.8t

-9.8t = -10

t = 10/9.8

t = 1.02secs

Hence your opponent have 1.02secs

(c, 0) i might be wrong so don't put full faith on my answer