PLEASE HELP on this question

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Step-by-step explanation:

a) (s+r)(x) = s(x) +r(x) = (x+1) +3x²

  (s+r)(x) = 3x² +x +1

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b) (s-r)(x) = s(x) -r(x) = (x +1) -(3x²)

  (s-r)(x) = -3x² +x +1

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c) (s·r)(-3) = s(-3)·r(-3) = (-3+1)·(3(-3)²) = (-2)(27)

  (s·r)(-3) = -54

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752