Work out the surface area of this solid quarter cylinder in terms of pi. r 10cm. h 16​

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  (320 +130π) cm²

Step-by-step explanation:

The perimeter of the base will be the sum of two radii and the arc length of a quarter circle:

  P = 2r +r(π/2) = r(2+π/2)

For a radius of 10 cm, the perimeter of the base is ...

  P = (10 cm)(2+π/2) = (20+5π) cm

The lateral area of the quarter-cylinder is the product of this perimeter and the height:

  LA = Ph = ((20 +5π) cm)(16 cm) = (320 +80π) cm²

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The total base area is the area of a half-circle of radius 10 cm, so is ...

  BA = 1/2πr² = (1/2)π(10 cm)² = 50π cm²

The total surface area is the sum of the base area and the lateral area:

  SA = BA +LA = (50π +(320 +80π)) cm² = (320 +130π) cm²

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

ensure that you have copied down this problem correctly.   .

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