How many liters each of a 35% acid solution in a 80% acid solution must be used to produce 60 L of a 65% acid solution?

Let x and y be the required amounts of the 35% and 60% acid solutions, respectively.

x liters of 35% acid solution contains 0.35x L of acid.

y liters of 80% acid solution contains 0.80y L of acid.

Together, a combined (x + y) L of mixed solutions contains (0.35x + 0.80y) L of acid.

You want to end up with 60 L of 65% acid solution, which means

x + y = 60

0.35x + 0.80y = 0.65 × 60 = 39

Solve for x and y :

y = 60 - x

0.35x + 0.80 (60 - x) = 39

0.35x + 48 - 0.80x = 39

0.45x = 9

x = 20

y = 40

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

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