Every week, Judy goes to the supermarket and buys the following: $5$ carrots at $\$1$ each, $3$ bottles of milk at $\$3$ each, $2$ pineapples at $\$4$ each, $2$ bags of flour at $\$5$ each, and a giant $\$7$ container of ice cream. This week the store has a sale and pineapples are half price. Judy also has a coupon for $\$5$ off any order of $\$25$ or over. How much money does Judy spend on this shopping trip

She spends $30 in total.

Step-by-step explanation:

Suppose that you buy X units of a given product with a price Y, then the total cost here is X*Y, with this we can solve our problem:

Every week Judy buys:

5 carrots, at $1 each, so she spends 5*$1 = $5 in carrots.

3 bottles of milk at $3, so she spends 3*$3 = $9 in milk bottles.

2 pineapples at $4 each (but the pineapples are at half price, so this week the pineapples cost $4/2 = $2), so she spends 2*$2 = $4 in pineapples.

2 bags of flour at $5 each, so she spends 2*$5 = $10 in flour.

1 giant container of ice cream, she spends $7 on it.

So the total money that she speends is:

$5 + $9 + $4 + $10 + $7 = $35

And she has a coupon for $5 in any order equal to or larger than $25, his order is larger than $25, so she can use the coupon.

So she will spend a total of $35 - $5 = $30

She spends $30 in total.

answer: the 4 kilogram bag

step-by-step explanation: this is because if you divide the number of kilograms into the total it will tell you how much each individual kilogram would be worth. 2 kilos is 7 and change 3 would be around 6 ish and the 4 kilo would be 4.6 and change and the 5 kilos would be like 4.88

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!