Suppose that a polynomial function of degree 5 with real coefficients has 4, -3i, and 9- 2i as zeros. Find the remaining zeros.

9514 1404 393

  3i, 9+2i

Step-by-step explanation:

Polynomials with real coefficients have complex zeros in conjugate pairs. The conjugates of the given complex zeros are the ones that are remaining:

  3i and 9+2i

x-3y=4

step-by-step e

statement #3: proof- ang is congruent to ang ecd : angles are congruent.  

step-by-step explanation:

1: the missing angles in statement #3  

a.) acb  

reason- the reason why the answer is acb is because angle ecd and angle acb are both the same size *that's what the word congruent means this is really simple.  

2: the missing word in reason #3  

c.) vertical  

reason- the reason why the answer is vertical is because the angles in that diagram on figure 2 is slanted, which is vertical, and the e and a both lay on vertical lines. along with the other's, but e and a are the 2 main points you want to focus on. and c is kind of like your starting point, because c is for both angles, not just one.  

i hope that was and understanding.