Using Euler's formula, how many edges does a polyhedron with 6 faces and 7 vertices have? ​

11 edges

Step-by-step explanation:

Euler's Formula:

V - E + F = 2, where V, E, and F are, respectively, the number of vertices, edges, and faces

We have:

F = 6, V = 7, E = ?

Substitute these numbers into formula and solve for E:

7 - E + 6 = 2

13 - E = 2

E = 13 - 2

E = 11

This polyhedron  has 11 edges