When a number is divided by 5 , the quotient is 8 and the remainder is 3. What is the number?
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80

Step-by-step explanation:

80 i am happy thank u enjoy your life hello hi hello

let's call the number "n", so we have a short term to talk about it

n will not exactly divisible by 5, because the remainder would be zero then.

since the remainder is 3, the number will be an integer that satisfies n = 5x + 3

example for 2x:

n = 5*2 + 3 = 13

if we devide 13 by 5, we would get 3 as remainder.

here the quotient would be 2 (the solution you get by dividing two numbers)

"x" is the quotient, so let's set it as 8

n = 5*8 +3

n = 43

checking it:

devide 43 by 5, you'll get 8 as the quotient and 3 as remainder.

hope it helps. Feel free to ask any question.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

mx+89b(-98)nb

step-by-step explanation: