If tenths of 5 + sqrt 11 is A and 5 - sqrt 11 is B and C is A+B. find c.
help me plzz!

1.5

Step-by-step explanation: Given:

                                       A=1/10×5 + 11²

                                        B= 5 - 11²

                              If     c = A + B

                                      c = ( 1/10×5 +11²) + ( 5 - 11² )

                                              = ( 5/10 + 121) + ( 5 - 121)

                                                = ( 121.5) + ( -120)

                                                    = 121.5 - 120

                                                    =  1.5  

if this is really you s much. i only have 3 points left and i have 2 questions to ask

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.