The area of rectangle is 105cm².If it length is 21 cm, what is its length and perimeter.​

length of other side is 5cm and the perimeter is 52

Step-by-step explanation:

The area is side x times side y.

Knowing that the area A is 105cm2 and side x is 21cm

A= x*y

105cm2= 21 y /21

Arranging for y we get

y= 105/21

y= 5 cm

The perimeter is all sides added up

P= 21+21+5+5=52cm

length 5cm and perimeter 52 cm

Step-by-step explanation:

length=area/breadth

=105/21

=5 cm

perimeter=2(length+breadth)

=2(5+21)

=52 cm

i dont know men

step-by-step explanation:

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0