A number increased by a% and decreased by 80% is 400. What is the number? will give brainliest

If we have a given number N, and we increase it by x%, then the new number is:

N + (x%/100%)*N

While if we decrease it by x%, the new number will be:

N - (x%/100%)*N

Now, we know that:

"A number increased by a% and decreased by 80% is 400. What is the number?"

First, we can not solve the problem, because we have two unknown values, the original number and the "a%", which I guess is a typo.

So, to be general with my answer, let's assume that the actual question is:

"A number increased by 50% and decreased by 80% is 400. What is the number?"

Then, if our original number is N and we increase it by 50%, the new number will be:

N + N*(50%/100%)

N + N*0.5

N*(1 + 0.5)

N*(1.5)

Now we decrease it by 80%, and that will be equal to 400, then:

N*1.5 - N*(1.5)*(80%/100%) = 400

N*1.5 - N*1.5*0.8 = 400

N*(1.5 - 1.5*0.8) = 400

N*(0.3) = 400

N = 400/0.3 = 1,333.33...

Remember that this is a kinda general solution, so you can understand how to solve this type of problem.

step-by-step explanation:

if u want da anser kill your teeser ifu hav wun

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this