Vail skied 2 km north, 2 km west, 1 km north, and 2 km west. How far was she from her starting point?

5.0645km

Step-by-step explanation:

For the first part of the journey where Vail skied 2 km north, 2 km west

displacement = √2² + (-2)²

displacement = √4+4

displacement = √8

displacement = 2√2 km

d1 = 2√2 km

For the second part of the journey where he skeid 1 km north, and 2 km west. How far was she from her starting point?

displacement = √1² + (-2)²

displacement = √1+4

displacement = √5

d2 = √5 km

Total displacement = d1 + d2

Total displacement = 2√2 + √5

Total displacement = 2(1.4142) + 2.2361

Total displacement = 2.8284+ 2.2361

Total displacement = 5.0645km

Hence she was 5.0645km from her starting point

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

49/6 is going to equal 8 1/6