Two shipments of components were received by a factory and stored in two separate bins. Shipment I has4% ofits contents defective, while shipment II has5% of its contents defective. If it is equally likely an employee willgo to either bin and select a component randomly, what is the probability a selected component is defective

0.045 = 4.5% probability a selected component is defective

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

In which

P(B|A) is the probability of event B happening, given that A happened.

is the probability of both A and B happening.

P(A) is the probability of A happening.

Probability of a defective component:

4% of 50%(shipment I)

5% of 50%(shipment II). So

0.045 = 4.5% probability a selected component is defective

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x