I will give brainliest! Given a rhombus has a side length of 15 and one diagonal has a length of 2x. Find the length of the second diagonal in terms of x. Show all work and leave your answer in radical form.

9514 1404 393

  2√(225 -x²)

Step-by-step explanation:

Let 2y be the length of the second diagonal. The half-diagonals and the side of the rhombus form a right triangle. The Pythagorean theorem tells us the relationship between sides and hypotenuse is ...

  x² +y² = 15²

  y² = 225 -x²

  2y = 2√(225 -x²2) . . . . the length of the second diagonal

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

answer:   (s+1)(s+4)

step-by-step explanation:

factor s2+5s+4

s2+5s+4

=(s+1)(s+4)