How do i find the area of a cone when all i get is radius and theta? radius = 5 theta = 52°

11.34464...

Step-by-step explanation:

it is not a 3-dimensional cone, it is a 2-dimensional segment of a circle. and you need to find its area.

which is also why you are asked to find the area, because for a 3-dimensional object you would have been asked about the volume of the surface.

now, about a circle and its segments.

you know how to get the area of a circle ?

it is pi×r²

that is for the full circle.

you know how many degrees it is to go "full circle" ?

360 degrees.

so, here we have only a segment of 52 degrees out of the full 360 degrees.

in other words we are dealing with 52/360 = 13/90 of the full circle.

all we have to do is therefore multiply the area of the full circle with that fraction, and we have our result.

pi×r²×13/90 = pi×5²×13/90 = pi×5×13/18 = 11.34464...

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."