Given f(x) = 6x + 2, find f(x – 3). A. f(x – 3) = 6x – 1
B. f(x – 3) = 6x – 16
C. f(x - 3) = x - 1
D. f(x – 3) = 6x2 – 16x - 6

B. f(x - 3) = 6x - 16

Concept:

When encountering a question that gives you a function and the evaluation value, then basically plug the given value into the function.

Solve:

Given function and value

f(x) = 6x + 2

f(x - 3)

Substitute the value into the given expression

f(x - 3) = 6 (x - 3) + 2

f(x - 3) = 6x - 18 + 2

f(x - 3) = 6x - 16

Hope this helps!! :)

Please let me know if you have any questions

6 equilateral triangles

let x and 400 - x be the two numbers.  

==> 0.80x + 0.85(400 - x) = 400 - 68 from the statement of the problem.  

< ==> 0.80x + 0.85(400 - x) = 400 - 68  

==> 340 - 0.05x = 332  

< ==> -0.05x = -8 ==> x = 160, the first number ==> 400 - x = 240, the second number.