Tan(3x/7 - π/5)= -√3/3

x is 7·π/30

Step-by-step explanation:

The given equation is presented as follows;

tan(3·x/7 - π/5) = (-√3)/3

We have that arctan (√3)/3 = π/6, and tangent of an angle is negative in the second quadrant, we get;

arctan (-√3)/3 = -π/6 = 5·π/6

∴ tan(-π/6) = -√3/3 = tan(3·x/7 - π/5)

-π/6 = 3·x/7 - π/5

x = (-π/6 + π/5) × 7/3 = (6·π - 5·π)/30 × 7/3 = π/30 × 7/3 = 7·π/30

x = 7·π/30

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?