UNDER THE TOPIC OF POLYNOMIAL IDENTITIES. REWRITE 27 AS A DIFFERENCE OF TWO NUMBERS

The Sum of Two Numbers is 27 and Their Difference is 27

The sum of two numbers is 27 and their difference is 27. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 27. In other words, x plus y equals 27 and can be written as equation A:

x + y = 27

The difference between x and y is 27. In other words, x minus y equals 27 and can be written as equation B:

x - y = 27

Now solve equation B for x to get the revised equation B:

x - y = 27

x = 27 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 27

27 + y + y = 27

27 + 2y = 27

2y = 0

y = 0

Now we know y is 0. Which means that we can substitute y for 0 in equation A and solve for x:

x + y = 27

x + 0 = 27

X = 27

Summary: The sum of two numbers is 27 and their difference is 27. What are the two numbers? 27 and 0 as proven here:

Sum: 27 + 0 = 27

Difference: 27 - 0 = 27

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!