The side-by-side stemplot below displays the arm spans, in centimeters, for two classes. A stemplot titled Arm Span (centimeters). For Class A, the values are 148, 151, 153, 155, 156, 159, 161, 162, 164, 165, 169, 169, 170, 171, 175, 176, 179, 179, 180, 182, 183, 186, 186, 190. For Class B, the values are 153, 155, 16, 160, 162, 162, 162, 163, 163, 165, 166, 167, 170, 173, 180, 181, 182, 189, 192, 202.

Which statement correctly compares the variability of the arm spans for Class A to that of Class B?

The arm spans for Class A have more variability than the arm spans for Class B.
The arm spans for Class B have less variability than the arm spans for Class A.
The arm spans for Class A have less variability than the arm spans for Class B.
The arm spans for Class B have about the same variability as the arm spans for Class A.

a. The arm spans for Class A have more variability than the arm spans for Class B.

Step-by-step explanation:

The stemplot for the Arm span is given for Class A and Class B. The variability of Class A are higher than variability of Class B. The arm spans of Class A have values greater than Class B. The mean of Class A is greater than Class B.

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt