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2·v - (u + w) = (5, 0, -10)

Step-by-step explanation:

The given values of the vectors are;

u = (2, -1, 3), v = (4, 0, -2), and w = (1, 1, 3)

The required vector is 2·v - (u + w)

2 × v = 2 × (4, 0, -2) = (8, 0, -4)

(u + w) = (2, -1, 3) + (1, 1, 3) = (3, 0, 6)

Therefore;

2·v - (u + w) = (8, 0, -4) - (3, 0, 6) = (5, 0, -10)

2·v - (u + w) = (5, 0, -10)

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204