Jessica has 28 coins. One fourth of them are quarters. Two thirds of the rest of the coins are dimes. The remaining ones are nickels. How many quarters, dimes, and nickels does he have? How much money does he have in coins? If he wants to buy 2 packs of cards, with each pack $1.35, how much money would he have left?

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Step-by-step explanation:

a) 1/4 of 28 = 28/4 = 7 coins are quarters.

  2/3 of (28 -7) = (2/3)(21) = 14 coins are dimes

The remaining 28 -7 -14 = 7 coins are nickels

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b) The amount of money in coins is ...

  7×$0.25 +14×$0.10 +7×$0.05 = $3.50 . . . in coins

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c) 2 packs of cards at $1.35 each will cost 2×$1.35 = $2.70. After the purchase, the remaining money would be ...

  $3.50 -2.70 = $0.80 . . . remaining

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step-by-step explanation: vsfdvsfvd

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length