a basketball player makes each free-throw with a probability of 0.3 and is on the line for a one-and-one free throw. (that is, a second throw is allowed only if the first is successful.) what is the probability that the player will score 0 points

0.7 = 70% probability that the player will score 0 points.

Step-by-step explanation:

For each free throw, we have these following probabilities:

0.3 probability the player makes.

0.7 probability the player misses.

What is the probability that the player will score 0 points?

He is only allowed the second if he misses the first, thus, he ends with 0 points only if he misses the first.

For any free throw:

0.7 probability the player misses, so 0.7 = 70% probability that the player misses the first free throw, and 0.7 = 70% probability that the player will score 0 points.

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).