The average life of an automobile tire of a certain manufacturer follows a Normal distribution, with a mean of 32,000 miles and a standard deviation of 1,250. Use the z-table to answer the question.

What tire life span separates the upper 30% of the life spans from the lower 70% of the life spans?

31,344 miles

32,650 miles

32,875 miles

33,250 miles

(B) 32,650 miles

the answer is 5636.7

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

the answer is. -82562234434584

step-by-step explanation:

bn,mn,n.vn.

step-by-step explanation: