ative section 3. a) The angle of elevation of the top of a tree observed from a point 60 m away from its foot is 45. Find the height of the tree, b) The angle of depression at a noint on 11​

The height of the tree is is 60m

Step-by-step explanation:

Let's answer a, as it is the only complete question.

We know that the angle of elevation of the top of a tree observed from a point 60m away, is 45°.

We can model this with a triangle rectangle, a sketch of it can be seen below (assuming that you are looking it from the ground).

You can see that the adjacent cathetus to the 45° angle is equal to 60m

And the opposite cathetus is the measure we want to find.

Now you can remember the trigonometric relation:

tan(a) = (opposite cathetus)/(adjacent cathetus).

So to find the height of the tree we need to solve:

tan(45°) = H/60m

This is just:

tan(45°)*60m = H  =60m

The height of the tree is is 60m

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation: