Find f such that f'(x) = 8x – 3. f(4) = 0​

y=29 / (4,29)

Step-by-step explanation:

By graphing and on Desmos. You'll be able to find that when x is 4, y is 29.

Similarly, you can plugin 4 into the original equation () Which looks like:

Additionally, you can change to as it is the exact same thing. With that in mind, you can do the same with and just change it to x=4. As you're wanting to know what the y-value is when x=4.

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

can you add an image ?

step-by-step explanation: