Two angles of a triangle have the same measure and the third one is 48 degrees greater than the measure of each of the other two. Find the measure of the LARGEST angle in the triangle.

Let the two equal angles each be x

Let the third angle be x + 48

Then ATQ

x + x + x + 48 = 180

3x + 48 = 180

3x = 180 - 48 (Angle Sum Property)

3x = 132

x = 132/3

x = 44

Now the two angles are each 44

And the largest angle = 44 + 48

= 92

Answered by Gauthmath must click thanks and mark brainliest