1)The sum of two consecutive multiples of 5 is55. Find these multiples. 2)The sum of three consecutive integers is 93. What are the integers?
3)If five is subtracted from three times a number, the result is 10. What is the number?

Part 1

Let the consecutive multiples be 5x and 5x + 5

ATQ

5x + 5x + 5 = 55

10x = 55 - 5

10x = 50

x = 5

Answer is 25 and 30

Part 2

Let the number be x , x + 1, x + 2

ATQ

x + x + 1 + x + 2 = 93

3x + 3 = 93

3x = 93 - 3

x = 90/3

x = 30

The integers are 30,31 and 32

Part 3

Let the number be x

ATQ

3x - 5 = 10

3x = 10 + 5

x = 15/3

x = 5

The number is 5

Answered by Gauthmath must click thanks and mark brainliest

child does not get an education so she can use the molla on junk