A ladder that is 10 feet long leaning against a wall perpendicular to the ground. The point at which the ladder touches the walk is 8 feet above the ground. How far away is the base of the ladder from the bottom of the wall ?

6 feet

Step-by-step explanation:

Gonna use the Pythagorean Theorem: a² + b² = c²

a² + 8² = 10²

a² + 64 = 100

Subtract both sides by 64

a² + 64 = 100

     -64     -64

a² = 36

Square root both sides

√a² = √36

a = 6 = length between bottom of the wall to the base of the ladder

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !