Select the correct answer from each drop-down menu. Drew is filing his tax return as single taxpayer. His taxable income is $39,000. Use the tax table provided to compute Drew's tax due and
effective tax rate.
Single Taxpayers: Income Brackets
Tax Income
Tax Owed
Rate Bracket
1096 O to 9,525 10% of taxable income
9,526 to $952.50 plus 12% of
1296
38,700 the excess over $9,525
$4,453.50 plus 22% of
2296
38,701 to
the excess over
82.500
$38,700
$14,089.50 plus 2496
82.501 to
2496
of the excess over
157.500
$82.500
$32,089.50 plus 3296
157.501 to
3296
of the excess over
200,000
$157.500
$45,689.50 plus 3596
200,001 to
3596
of the excess over
500,000
$200,000
$150,689.50 plus 3796
3796 > 500,000 of the excess over
55

The given tax rates are as follows:

Single Taxpayers: Income Brackets

Tax Income          Rate Bracket             Tax Owed              

O to 9,525          10%                     10% of taxable income

9,526 to38,700    12%                $952.50 plus 12% of  38,700 the excess                                                                                        over

$38,701 to 82,500  22 %                $4,453.50 plus 22% of 38,701                                                                                     the excess over

82,501 to 157,500     24%    $14,089.50 plus 24%  of the excess over

                                                                 157,500

157,501 to  200,000     32%     $ 32089.50  plus 32% of the excess over

200,001 to   500,000     35%      45,689.50 plus 35% of the excess over

500,000 >                37%         $150,689.50 plus 37% of 500,000 of the    

                                                               excess over

The taxable income lies in the tax rate range of   $38,701 to 82,500.

Therefore the tax would be  

 $4,453.50 + 22% of (39,000-38,701=299)

 $4,453.50 + 22% of 299

 $4,453.50 + 65.78

= $ 4519.28

The taxable income lies in the tax rate range of  $38,701 to 82,500.

Due and effective tax rate is $4,453.50 plus 22% of 38,701 the excess over

The calculated tax is $ 4519.28

i think it's eleven too, don't woosh me here, but according to the "experts" it's 2.

the proof starts from the peano postulates, which define the natural

numbers n. n is the smallest set satisfying these postulates:

  p1.   1 is in n.

  p2.   if x is in n, then its "successor" x' is in n.

  p3.   there is no x such that x' = 1.

  p4.   if x isn't 1, then there is a y in n such that y' = x.

  p5.   if s is a subset of n, 1 is in s, and the implication

      (x in s => x' in s) holds, then s = n.

then you have to define addition recursively:

  def: let a and b be in n. if b = 1, then define a + b = a'

      (using p1 and p2). if b isn't 1, then let c' = b, with c in n

      (using p4), and define a + b = (a + c)'.

then you have to define 2:

  def:   2 = 1'

2 is in n by p1, p2, and the definition of 2.

theorem:   1 + 1 = 2

proof: use the first part of the definition of + with a = b = 1.

      then 1 + 1 = 1' = 2   q.e.d.

note: there is an alternate formulation of the peano postulates which

replaces 1 with 0 in p1, p3, p4, and p5. then you have to change the

definition of addition to this:

  def: let a and b be in n. if b = 0, then define a + b = a.

      if b isn't 0, then let c' = b, with c in n, and define

      a + b = (a + c)'.

you also have to define 1 = 0', and 2 = 1'. then the proof of the

theorem above is a little different:

proof: use the second part of the definition of + first:

      1 + 1 = (1 + 0)'

      now use the first part of the definition of + on the sum in

      parentheses:   1 + 1 = (1)' = 1' = 2   q.e.d.