Given the triangle below, what is m 2A, rounded to the nearest tenth? B
18
11
309
A
C
Triangle not drawn to scale
A. 17.8
OB. 20.4
O C. 24.2
D. 26.8

9514 1404 393

  A.  17.8°

Step-by-step explanation:

We have an angle and an opposite side, so we can use the law of sines to find the angle of interest.

  sin(A)/a = sin(C)/c

  A = arcsin(a/c·sin(C)) = arcsin(11/18·1/2) = arcsin(11/36)

  A ≈ 17.7916° ≈ 17.8°

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

d. all of the above

step-by-step explanation: