In the hand simulation of the simple processing system(the example in lecture 2), suppose that a constant setup time of 3 minutes was required once a part enter the drill press but before its service could actually begin. When a setup is going on, regard the drill press as being busy. Plot the total number of parts in system as a function of simulated time. As numerical output performance measures, report the total production(number of parts produced), the average and maximum waiting time in queue, the average and maximum total time in system, the time-average and maximum number of parts in queue, and the drill press utilization. Redo the hand simulation and discuss the results.

your answer is a

step-by-step explanation:

4*4*4*4=256

i would need to see the dot plot : )

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)