If two resistors with resistances R1 and R2 are connected in parallel, as in the figure below, then the total resistance R, measured in ohms (Ω), is given by 1/R = 1/R1 + 1/R2 . If R1 and R2 are increasing at rates of 0.3 Ω/s and 0.2 Ω/s, respectively, how fast is R changing when R1 = 60 Ω and R2 = 80 Ω? (Round your answer to three decimal places.)

The rate of change of R with time in the given equation is 0.004 ohm/s

Given parameters:

To find:

First determine the value of R from the given equation;

Finally, to determine the rate of change of R, differentiate the given equation.

Thus, from the given equation the rate of change of R with time is 0.004 ohm/s

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