Choose the function that has two different zeros. A. j(x) = x2 + 6x + 9
B. k(x) = x2 – 8x + 16
C. h(x) = x2 + 2x + 1
D. g(x) = x2 – 64

D

Step-by-step explanation:

The first 3 are perfect squares and have 2 equal zeros

j(x) = x² + 6x + 9 = (x + 3)² with zeros x = - 3 , multiplicity of 2

k(x) = x² - 8x + 16 = (x - 4)² with zeros x = 4 , multiplicity of 2

h(x) = x² + 2x + 1 = (x + 1)² with zeros x = - 1 , multiplicity of 2

g(x)

x² - 64 is a difference of squares

(x - 8)(x + 8) = 0

with zeros x = - 8, x = 8 ← 2 different zeros

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )