Wilsen creates, among other things, footballs. These should be, given their name, exactly one foot long, with a LSL of 11.95 inches and an USL of 12.05 inches. Currently, the production process generates footballs with an average length of 12.03 inches and a standard deviation of 0.01 inches. By how much can we improve the process capability of this process if we centered the mean?

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

its a i did it myself

step-by-step explanation: