Suppose the distribution of home sales prices has mean k300, 000 and standard deviation of k50, 000.
(i) Determine the price range in which at least 75% of the houses sold.
[4 Marks]
(ii) Determine the minimum percentage of the houses that should sell for
prices between k150, 000 and k450, 000. [4 Marks]
(iii) Determine the minimum percentage of the houses that should sell for
prices between k170, 000 and k430, 000

Given:

Mean,

Standard deviation,

The Chebyshev theorem will be used for the solution of the given query,

i.e.,

(i)

⇒

The lower limit will be:

=

=

=

The upper limit will be:

=

=

=

hence,

The 75% houses sold are between:

⇒ (200000, 400000)

(ii)

⇒

By putting the values, we get

now,

⇒

              (%)

hence,

88.88% houses sold between 150000 and 450000.      

(iii)

⇒

By putting the values, we get

now,

⇒

              (%)

hence,

85.21% houses are sold between 170000 and 430000.

Learn more:

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

explanation:

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