Jane has 200 feet of fencing to enclose a rectangular vegetable garden. One side of the garden will be alongside Jane's house so only three sides will need to be fenced. What is the largest area that can be enclosed by the 200 feet of fencing?

10,000 ft^2

Step-by-step explanation:

Let x represent length alongside Jane’s house and y represent width of garden.

We have been given that Jana has 200 feet of fencing to enclose a rectangular vegetable garden. One side of the garden will be alongside Jane’s house so only three sides will need to be fenced.

The fencing on 3 sides of garden will be equal to perimeter of garden on three sides.

p = x + 2y

200 = x + 2y

We know that area of rectangle is equal to length times width that is A = xy .

From perimeter equation, we will get:

x = 200 - 2y

Substituting this value in area equation, we will get:

A(y) = (200-y)y

Now, we need to find derivative of area of function.

A(y) = 200y - y^2

A'(y) = 200 - 2y

Now, we will set derivative equal to 0 to find critical points.

200 - 2y = 0

200 = 2y

y = 100

So thus the area will be maximum when 100.

A(y) = 200y - y^2

Substituting y for 100 we get A(100) = 10,000

choice b is correct

step-by-step explanation:

we have been given the following system of linear inequalities;

we are required to graphically determine the solution to these system of inequalities. using a graphing tool, the solution is as shown in the attachment below;

answer: i realy don't get it that much can you me figer it out pleas you

step-by-step explanation: