Find the point on y axis which is equidistant from the point (5,-2) and (-3,2)

(0, -2)

Step-by-step explanation:

a point on the y-axis. that means x=0.

so, the distance of (5, -2) to (0, y) is the same as the distance from (-3, 2) to (0, y).

the distance between (5, -2) and (0, y) is based on Pythagoras (the differences in x and y directions are the sides of a right-angled triangle, and the distance is its Hypotenuse, its baseline) :

distance² = (5-0)² + (-2 - y)² = 25 + 4 + 4y + y² = 29+4y+y²

but it is also

distance² = (-3-0)² + (2 - y)² = 9 + 4 - 4y + y² = 13 - 4y + y²

so, we get

29 + 4y + y² = 13 - 4y + y²

29 + 4y = 13 - 4y

16 = -8y

y = -16/8 = -2

their, the point on the y-axis being equidistant to both points is (0, -2)

power property.

ii6tyhj7 juj3yyj333ju jmyhthhtk7h jg hajj jiijh