Find ''m'' and ''c'' of 3-2x+y=0 by comparing with y=mx+c

m=-2 c=3

Step-by-step explanation:

y=mx+c

rearrange

-mx-c+y=0

original

y=2x-3

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18