Question 5 10 pts Which function represents the inverse of f(x) = (x + 6)2 - 5? of 1(1) = V1 + 5 - 6 of '(x) = (x + 5)2 - 6 of '(x) = V1 – 6 + 5 Of '(x) = (x + 6 – 5​

f(x)^-1(x) =sqrt(x+5) -6

Step-by-step explanation:

f(x) = (x + 6)^2 - 5

y =  (x + 6)^2 - 5

Exchange x and y and solve for y

x = (y + 6)^2 - 5

Add 5 to each side

x+5 =  (y + 6)^2 - 5+5

x+5 =  (y + 6)^2

Take the square root of each side

sqrt(x+5 )= sqrt( (y + 6)^2 )

sqrt(x+5 )=(y + 6)

Subtract 6 from each side

sqrt(x+5 ) -6=y + 6-6

sqrt(x+5) -6 = y

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

da freeck kinda math is this just drop out

step-by-step explanation: