Complete the square to rewrite y = x^2 + 6x + 2 in vertex form. Then state whether the vertex is a maximum or a minimum and give its coordinates. A. Maximum at (–3, –7) B. Minimum at (–3, –7) C. Minimum at (3, –7) D. Maximum at (3, –7)

y = (x+3)^2 - 7

minimum at (-3, -7)

Step-by-step explanation:

to complete the square first take half the x coefficient which in this case is 6/2 = 3

then expand (x+3)^2 which gives you x^2 + 6x + 9

to get the equation you want you need to subtract 7

so the completed square form is y = (x+3)^2 - 7

since the x coefficient is > 0 it is a minimum

and the point is (-3, -7)

pls thank and mark brainliest

Provided by Guathmaths

the answer is d

step-by-step explanation: