A bag contains 42 red, 45 green, 20 yellow, and 32 purple candies. You
pick one candy at random. Find the
probability that it is green or yellow.

 =65/139

Step-by-step explanation:

42 red, 45 green, 20yellow, and 32 purple candies = 139 candies

P( green or yellow) = green or yellow / total

                                =(45+20) / 139

                                  =65/139

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this