Write the point-slope form of the line passing through (2, -12) and perpendicular to y = 3x.

y+12 = -1/3(x-2)

Step-by-step explanation:

y = 3x

The slope is 3

Lines perpendicular have a slope that is the negative reciprocal

-1/3 is the slope of a line that is perpendicular

Point slope form is

y-y1 = m(x-x1)  where m is the slope and (x1,y1) is the point on the line

y --12 = -1/3(x-2)

y+12 = -1/3(x-2)

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step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)