Santiago receives ​$179 per year in simple interest from three investments. Part is invested at​ 2%, part at​ 3%, and part at​ 4%. There is​ $500 more invested at​ 3% than at​ 2%. The amount invested at​ 4% is four times the amount invested at​ 3%. Find the amount invested at each rate.

9514 1404 393

Step-by-step explanation:

Let x represent the amount invested at 3%. Then (x -500) is the amount invested at 2%, and 4x is the amount invested at 4%. The total interest income is ...

  0.02(x -500) + 0.03x + 0.04(4x) = 179

  0.21x -10 = 179 . . . . . simplify

  0.21x = 189 . . . . . . . . add 10

  x = 900 . . . . . . . . . . . divide by 0.21

  x -500 = 400

  4x = 3600

$400 is invested at 2%; $900 is invested at 3%, $3600 is invested at 4%.

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation:

b, i believe, but not sure.