The total number of​ restaurant-purchased meals that the average person will eat in a​ restaurant, in a​ car, or at home in a year is 193 . The total number of these meals eaten in a car or at home exceeds the number eaten in a restaurant by 15 . Thirty more​ restaurant-purchased meals will be eaten in a restaurant than at home. Find the number of​ restaurant-purchased meals eaten in a​ restaurant, the number eaten in a​ car, and the number eaten at home.

9514 1404 393

Step-by-step explanation:

Let r, c, h represent the numbers of meals eaten in a restaurant, car, and at home, respectively. The problem statement tells us of the relations ...

  r + c + h = 193

  -r + c + h = 15

  r + 0c -h = 30

Add the last two equations:

  (-r +c +h) +(r -h) = (15) +(30)

  c = 45

Add the first two equations:

  (r + c + h) +(-r + c + h) = (193) +(15)

  2c +2h = 208

  h = 104 -c = 59 . . . . solve for h, substitute for c

The last equation can be used to find r.

  r = 30 +h = 30 +59 = 89

89 meals are eaten in a restaurant; 45 meals in a car; and 59 at home.

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

answer: x=60