Quad DEFG with mZD= (12x - 4), mZE = (18x + 4)ºmZF = (15x + 10), and
m2G= (5x)
What is the value of x?

x = 7°

Explanation:

We know that sum of angles of a quadilateral is = 360°

Therefore ATQ

⇒ (12x-4)+(18x+4)+(15x+10)+(5x) = 360

⇒ (12x + 18x + 15x + 5x) + (-4+4+10) = 360

⇒ 50x + 10 = 360

⇒ 50x = 360-10

⇒ 50x = 350

⇒ x = 350/50

⇒ x = 7

Therefore value of x is 7°

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